The mass of ammonia in grams produced when 2.8 kg of dinitrogen quantitatively reacts with 1 kg of dihydrogen is _______.
Answer (integer)
3400
Solution
N<sub>2</sub>(g) + 3H<sub>2</sub>(g) $\to$ 2NH<sub>3</sub>(g)
<br><br>Number of moles of N<sub>2</sub> = ${{2.8 \times {{10}^3}} \over {28}}$ = 100
<br><br>Number of moles of H<sub>2</sub> = ${{1000} \over 2}$ = 500
<br><br>Here N<sub>2</sub> is limiting reagent.
<br><br>$\therefore$ Number of moles of NH<sub>3</sub> produced = 2 $\times$ 100 = 200
<br><br>Mass of NH<sub>3</sub> produced = 200 × 17 = 3400 gm
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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