5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL) of this solution would be required to prepare 500 mL of 0.1 M solution? _____________
Given : Molar Mass of Na, O and H is 23, 16 and 1 g mol$^{-1}$ respectively
Answer (integer)
180
Solution
Molarity of solution $=\frac{5}{(40)} \frac{(1000)}{(450)}$
<br/><br/>
$\Rightarrow M \times V=500 \times .1$
<br/><br/>
$\Rightarrow \frac{5}{40} \times \frac{1000}{450} \times V=500 \times 0.1$
<br/><br/>
$\mathrm{V}=180 \mathrm{~mL}$
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
This question is part of PrepWiser's free JEE Main question bank. 163 more solved questions on Some Basic Concepts of Chemistry are available — start with the harder ones if your accuracy is >70%.