Butane reacts with oxygen to produce carbon dioxide and water following the equation given below.

$$ \mathrm{C}_4 \mathrm{H}_{10}(\mathrm{~g})+\frac{13}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow 4 \mathrm{CO}_2(\mathrm{~g})+5 \mathrm{H}_2 \mathrm{O}(\mathrm{l}) $$

If 174.0 kg of butane is mixed with 320.0 kg of $\mathrm{O}_2$, the volume of water formed in liters is

_____________. (Nearest integer)

[Given : (a) Molar mass of C, H, O are $12,1,16 \mathrm{~g} \mathrm{~mol}^{-1}$ respectively, (b) Density of water $\left.=1 \mathrm{~g} \mathrm{~mL}^{-1}\right]$

<p>The chemical reaction between butane ($\mathrm{C}_4\mathrm{H}_{10}$) and oxygen ($\mathrm{O}_2$) to produce carbon dioxide ($\mathrm{CO}_2$) and water ($\mathrm{H}_2\mathrm{O}$) can be represented by the following equation:</p> <p>$ \mathrm{C}_4\mathrm{H}_{10}(\mathrm{g}) + \frac{13}{2} \mathrm{O}_2(\mathrm{g}) \rightarrow 4 \mathrm{CO}_2(\mathrm{g}) + 5 \mathrm{H}_2\mathrm{O}(\mathrm{l}) $</p> <p>Given that we have 174.0 kg of butane and 320.0 kg of oxygen, we are tasked with calculating the volume of water produced in liters.</p> <p><strong>Mole Calculation for Water:</strong></p> <p><p>The stoichiometry of the reaction shows that 5 moles of water are produced per 13/2 moles of oxygen.</p></p> <p><p>Using the moles of oxygen available from input, calculate the moles of water produced:</p></p> <p>$ \text{Moles of } \mathrm{H}_2\mathrm{O} = 5 \times \frac{2}{13} \times (10 \times 10^3) $</p> <ol start="2"> <p><strong>Mass of Water Produced:</strong></p> <p>Calculate the mass of water using the molar mass of water (18 g/mol):</p> <p>$ \text{Mass of } \mathrm{H}_2\mathrm{O} = \left(\frac{10^5}{13}\right) \times 18 $</p> <p>The result will be:</p> <p>$ = 1.3846 \times 10^5 \ \text{g} $</p> <ol start="3"> <p><strong>Volume of Water:</strong></p> <p>Convert the mass of water to volume, considering the density of water is $1 \ \text{g/mL}$ (or $1 \ \text{g/L}$):</p> <p>$ \text{Volume of } \mathrm{H}_2\mathrm{O} = 138.46 \ \text{liters} $</p> <p>Therefore, the volume of water formed is approximately 138 liters when rounded to the nearest integer.</p>