The molarity of a $70 \%$ (mass/mass) aqueous solution of a monobasic acid (X) is _________ $\times 10^{-1}$ M (Nearest integer)
[Given: Density of aqueous solution of (X) is $1.25 \mathrm{~g} \mathrm{~mL}^{-1}$
Molar mass of the acid is $70 \mathrm{~g} \mathrm{~mol}^{-1}$ ]
Answer (integer)
125
Solution
<p>Assuming 100 gm solution contain 70 gm solute.</p>
<p>Volume of 100 gm solution will be $\frac{100}{1.25} \mathrm{ml}$.</p>
<p>Molarity $=\frac{70 / 70}{100 / 1.25} \times 1000=12.5$ or $125 \times 10^{-1}$</p>
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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