'25 volume' hydrogen peroxide means
Solution
Molarity of $\mathrm{H}_{2} \mathrm{O}_{2}$ soln $=\frac{\text { volume strength }}{11.2}$
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$=\frac{25}{11.2}=2.23 \mathrm{M}$
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$\therefore$ amount of $\mathrm{H}_{2} \mathrm{O}_{2}$ in one litre $=2.23 \times 34=75 \mathrm{gm}$
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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