The molarity of HNO3 in a sample which has
density 1.4 g/mL and mass percentage of 63%
is _____.
(Molecular Weight of HNO3 = 63)
Answer (integer)
14
Solution
%w/w = 63%
<br><br>d<sub>solution</sub> = 1.4 g/ml
<br><br>Molarity = <span style="display: inline-block;vertical-align: middle;">
<div style="text-align: center;border-bottom: 1px solid black;">%w/w $\times$ d<sub>solution</sub></div>
<div style="text-align: center;">Moleculer weight of Solute</div>
</span>.$\times$ 10
<br><br>= ${{63 \times 1.4 \times 10} \over {63}}$ = 14 M
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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