A solution of sugar is obtained by mixing $200 \mathrm{~g}$ of its $25 \%$ solution and $500 \mathrm{~g}$ of its $40 \%$ solution (both by mass). The mass percentage of the resulting sugar solution is ___________ (Nearest integer)
Answer (integer)
36
Solution
<p>Let's first calculate the amount of sugar in each of the solutions :</p>
<ol>
<li><p>In the 25% sugar solution, the amount of sugar is 25% of 200 g, which equals 50 g.</p>
</li>
<li><p>In the 40% sugar solution, the amount of sugar is 40% of 500 g, which equals 200 g.</p>
</li>
</ol>
<p>Now, let's mix these two solutions together:</p>
<p>The total amount of sugar in the combined solution is 50 g (from the 25% solution) + 200 g (from the 40% solution) = 250 g.</p>
<p>The total weight of the combined solution is 200 g (of the 25% solution) + 500 g (of the 40% solution) = 700 g.</p>
<p>Therefore, the mass percentage of sugar in the combined solution is $=\frac{250}{700} \times 100$ = 35.71%</p>
<p>Rounding to the nearest integer gives 36%. So, the mass percentage of the resulting sugar solution is 36%.</p>
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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