Xg of benzoic acid on reaction with aq $\mathrm{NaHCO}_3$ released $\mathrm{CO}_2$ that occupied 11.2 L volume at STP.
X is _________ g.
Answer (integer)
61
Solution
<p>$\begin{aligned} & \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}+\mathrm{NaHCO}_3 \rightarrow \mathrm{C}_6 \mathrm{H}_5 \mathrm{COO} \mathrm{Na}^{+} \\ & +\mathrm{H}_2 \mathrm{O}+\mathrm{CO}_2\end{aligned}$</p>
<p>$$\begin{aligned}
& \mathrm{x} \mathrm{~gm} \quad \text{11.2 L}\\
& \text { mole of } \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}=\text { mole of } \mathrm{CO}_2=\frac{11.2}{22.4}=0.5 \\
& \text { mass of } \mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}=\mathrm{x}=0.5 \times 122=61 \mathrm{gm}
\end{aligned}$$</p>
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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