10.30 mg of O2 is dissolved into a liter of sea water of density 1.03 g/mL. The concentration of O2 in ppm is__________.
Answer (integer)
10
Solution
1030 gm of sea water contains = 10.3 × 10<sup>–3</sup> gm
<br><br>10<sup>6</sup>
gm of sea water contains = ${{10.3 \times {{10}^{ - 3}}} \over {1030}} \times {10^6}$ = 10 ppm
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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