If the concentration of glucose (C6H12O6) in blood is 0.72 g L$-$1, the molarity of glucose in blood is ____________ $\times$ 10$-$3 M. (Nearest integer)
[Given : Atomic mass of C = 12, H = 1, O = 16 u]
Answer (integer)
4
Solution
[Glucose] = ${{C(gm/l)} \over {M(gm/mol)}} = {{0.72} \over {180}} = 4 \times {10^{ - 3}}$ M
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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