The moles of methane required to produce 81 g of water after complete combustion is _____________ $\times$ 10$-$2 mol. [nearest integer]
Answer (integer)
225
Solution
$\mathrm{CH}_4+2 \mathrm{O}_2 \rightarrow \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O}$<br/><br/>
POAC on $\mathrm{H}$ atom<br/><br/>
$$
\begin{aligned}
&\mathrm{n}_{\mathrm{CH} 4} \times 4=\mathrm{n}_{\mathrm{H} 2 \mathrm{O}} \times 2 \\\\
&\mathrm{n}_{\mathrm{CH}_4}=\frac{81}{18} \times 2 \times \frac{1}{4}=\frac{81}{36} \\\\
&\mathrm{n}_{\mathrm{CH}_4}=2.25 \\\\
&=225 \times 10^{-2}
\end{aligned}
$$<br/><br/>
Nearest Integers $=225$
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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