$0.5 \mathrm{~g}$ of an organic compound $(\mathrm{X})$ with $60 \%$ carbon will produce __________ $\times 10^{-1} \mathrm{~g}$ of $\mathrm{CO}_{2}$ on complete combustion.
Answer (integer)
11
Solution
Mass of Carbon $=12$<br/><br/>
Molar Mass of $\mathrm{CO}_2=12+(16 \times 2)=44$<br/><br/>
Mass of Compound $=0.5 \mathrm{~g}$<br/><br/>
$$
\begin{aligned}
&\% \text { of } \mathrm{C} =\frac{\text { Molar mass of } \mathrm{C} \times \text { Mass Of } \mathrm{CO}_2}{\text { Mass Of Compound } \times \text { Molar Mass } \mathrm{Of} ~ \mathrm{CO}_2} \\\\
&\frac{60}{100} =\frac{12 \times x}{0.5 \times 44} \\\\
&1.1 =x \\\\
&x =11 \times 10^{-1}
\end{aligned}
$$
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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