Number of moles of methane required to produce $22 \mathrm{~g} \mathrm{~CO}_{2(\mathrm{~g})}$ after combustion is $\mathrm{x} \times 10^{-2}$ moles. The value of $\mathrm{x}$ is _________.
Answer (integer)
50
Solution
<p>$$\mathrm{CH}_{4(\mathrm{~g})}+2 \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_{2(\mathrm{~g})}+2 \mathrm{H}_2 \mathrm{O}_{(\ell)}$$</p>
<p>$\mathrm{n}_{\mathrm{CO}_2}=\frac{22}{44}=0.5 \text { moles }$</p>
<p>So moles of $\mathrm{CH}_4$ required $=0.5$ moles i.e. $50 \times 10^{-2} \mathrm{~mole}$</p>
<p>$\mathrm{x}=50$</p>
About this question
Subject: Chemistry · Chapter: Some Basic Concepts of Chemistry · Topic: Mole Concept
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