BeO reacts with HF in presence of ammonia to give [A] which on thermal decomposition produces [B] and ammonium fluoride. Oxidation state of Be in [A] is ____________.
Answer (integer)
2
Solution
$$
\mathrm{BeO}+2 \mathrm{NH}_3+4 \mathrm{HF} \longrightarrow\underset{\text { (A) }}{\left(\mathrm{NH}_4\right)_2\left[\mathrm{BeF}_4\right]}
$$<br/><br/>
$$
\left(\mathrm{NH}_4\right)_2\left(\mathrm{BeF}_4\right) \stackrel{\text { Heating }}{\longrightarrow} \underset{\text { (B) }}{\mathrm{BeF}_2}+2 \mathrm{NH}_4 \mathrm{~F}
$$<br/><br/>
Oxidation State of Be in $(A)$ is $(+2)$
About this question
Subject: Chemistry · Chapter: s-Block Elements · Topic: Alkali Metals
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