Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: $\mathrm{LiF}$ is sparingly soluble in water.
Reason R: The ionic radius of $\mathrm{Li}^{+}$ ion is smallest among its group members, hence has least hydration enthalpy.
In the light of the above statements, choose the most appropriate answer from the options given below.
Solution
LiF is sparingly soluble in water.
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The low solubility of LiF in water is due to its high lattice enthalpy (Since $\mathrm{Li}^{+}$ and $\mathrm{F}^{-}$ are small in size). Also, due to small size of $\mathrm{Li}^{+}$, its hydration enthalpy is high.
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Hence, Assertion is true but Reason is false
About this question
Subject: Chemistry · Chapter: s-Block Elements · Topic: Alkali Metals
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