The difference in electronegativity between fluorine (4.0) and cesium (0.7) is $x \times 10^{-1}$. Find $x$.
Answer (integer)
33
Solution
Difference $= 4.0 - 0.7 = 3.3 = 33 \times 10^{-1}$. So $x = 33$.
About this question
Subject: Chemistry · Chapter: Periodic Table and Periodicity · Topic: Periodic Trends
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