The oxide that gives H2O2 most readily on treatment with H2O is :
Solution
(a) PbO<sub>2</sub> + 2H<sub>2</sub>O $\to$ Pb(OH)<sub>4</sub><br><br>(b) Na<sub>2</sub>O<sub>2</sub> + 2H<sub>2</sub>O $\to$ 2NaOH + H<sub>2</sub>O<sub>2</sub><br><br>this reaction is possible at room temperature<br><br>(c) SnO<sub>2</sub> + 2H<sub>2</sub>O $\to$ Sn(OH)<sub>4</sub><br><br>(d) Acidified BaO<sub>2</sub> . 8H<sub>2</sub>O gives H<sub>2</sub>O<sub>2</sub> after evaporation.
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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