Consider the following reactions:
PCl3 + H2O $\to$ A + HCl
A + H2O $\to$ B + HCl
The number of ionisable protons present in the product B is _______________.
Answer (integer)
2
Solution
$\mathrm{PCl}_{3}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \underset{\text{A}}{\mathrm{P}(\mathrm{OH}) \mathrm{Cl}_{2}}+\mathrm{HCl}$
<br/><br/>
$$
\underset{\mathrm{A}}{\mathrm{P}(\mathrm{OH})_{2} \mathrm{Cl}_{2}}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \underset{\text{B}}{\mathrm{P}(\mathrm{OH})_{2} \mathrm{Cl}}+\mathrm{HCl}
$$
<br/><br/>
Hydrogen attached with oxygen are ionisable. Hence number of ionisable protons present in compound $B$ are 2.
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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