The reaction of $\mathrm{H}_{2} \mathrm{O}_{2}$ with potassium permanganate in acidic medium leads to the formation of mainly :
Solution
The reaction of $\mathrm{KMnO}_{4}$ with $\mathrm{H}_{2} \mathrm{O}_{2}$ in acidic medium is as
<br/><br/>
$$
\begin{aligned}
2 \mathrm{KMnO}_{4}+3 \mathrm{H}_{2} \mathrm{SO}_{4}+5 \mathrm{H}_{2} \mathrm{O}_{2} \\
& \rightarrow \mathrm{K}_{2} \mathrm{SO}_{4}+2 \mathrm{MnSO}_{4}+8 \mathrm{H}_{2} \mathrm{O}+5 \mathrm{O}_{2}
\end{aligned}
$$<br/><br/>
$\therefore \mathrm{Mn}^{2+}$ will be formed as the product.
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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