The oxidation state of oxygen in OF₂ (oxygen difluoride) is $x$.
Answer (integer)
2
Solution
In OF₂, F is more electronegative so it gets -1 each. Let O be x: x + 2(-1) = 0 ⇒ x = +2.
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 16: Oxygen Family
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