Among the following allotropic forms of sulphur, the number of allotropic forms, which will show paramagnetism is _________.
(A) $\alpha$-sulphur
(B) $\beta$-sulphur
(C) S2-form
Answer (integer)
1
Solution
Only S<sub>2</sub>-form of sulphur is paramagnetic in nature. Because S<sub>2</sub> is like O<sub>2</sub> i.e. paramagnetic as per molecular orbital theory. It contains unpaired electron. While $\alpha$-sulphur and $\beta$-sulphur are diamagnetic as they do not have unpaired electron.
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
This question is part of PrepWiser's free JEE Main question bank. 300 more solved questions on p-Block Elements are available — start with the harder ones if your accuracy is >70%.