Reaction of thionyl chloride with white phosphorus forms a compound [A], which on hydrolysis gives [B], a dibasic acid. [A] and [B] are respectively :
Solution
$$
\begin{aligned}
& \mathrm{P}_4+8 \mathrm{SOCl}_2 \rightarrow \underset{[\mathrm{A}]}{4 \mathrm{PCl}_3}+4 \mathrm{SO}_2+2 \mathrm{~S}_2 \mathrm{Cl}_2 \\\\
& \mathrm{PCl}_3+3 \mathrm{H}_2 \mathrm{O} \rightarrow \underset{[B]}{\mathrm{H}_3 \mathrm{PO}_3}+3 \mathrm{HCl}
\end{aligned}
$$
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
This question is part of PrepWiser's free JEE Main question bank. 300 more solved questions on p-Block Elements are available — start with the harder ones if your accuracy is >70%.