At 298.2 K the relationship between enthalpy of bond dissociation (in kJ mol$-$1) for hydrogen (EH) and its isotope, deuterium (ED), is best described by :
Solution
Enthalpy of bond dissociation (kJ/mole) at 298.2 K <br><br>For, Hydrogen = 435.88<br><br>For, Deuterium = 443.35<br><br>$\therefore$ ${E_H} \simeq {E_D} - 7.5$
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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