Potassium dichromate acts as a strong oxidizing agent in acidic solution. During this process, the oxidation state changes from :
Solution
<p>$\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}$ acts as a strong oxidising agent in acidic medium. During this process, oxidation state of $\mathrm{Cr}$ changes from $+6$ to $+3$.</p>
<p>$$
\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+14 \mathrm{H}^{+}+6 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cr}^{3+}+7 \mathrm{H}_{2} \mathrm{O}
$$</p>
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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