The interhalogen compound formed from the reaction of bromine with excess of fluorine is a :
Solution
$$\mathrm{Br}_{2}+\underset{\text { (Excess) }}{5 \mathrm{~F}_{2}} \longrightarrow 2 \mathrm{BrF}_{5}$$
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If $\mathrm{BrF}_{5}$ undergoes hydrolysis it will produce halide.
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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