When borax is heated with $\mathrm{CoO}$ on a platinum loop, blue coloured bead formed is largely due to :
Solution
$\mathrm{Na}_{2} \mathrm{~B}_{4} \mathrm{O}_{7} \stackrel{\Delta}{\longrightarrow} 2 \mathrm{NaBO}_{2}+\mathrm{B}_{2} \mathrm{O}_{3}$
<br/><br/>$\mathrm{B}_{2} \mathrm{O}_{3}+\mathrm{CoO} \rightarrow \mathrm{Co}\left(\mathrm{BO}_{2}\right)_{2}$
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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