Easy MCQ +4 / -1 PYQ · JEE Mains 2022

Match List I with List II

List I List II
(A) N$_2$(g) + 3H$_2$(g) $\to$ 2NH$_3$(g) (I) Cu
(B) CO(g) + 3H$_2$(g) $\to$ CH$_4$(g) + H$_2$O(g) (II) Cu/ZnO $-$ Cr$_2$O$_3$
(C) CO(g) + H$_2$(g) $\to$ HCHO(g) (III) Fe$_x$O$_y$ + K$_2$O + Al$_2$O$_3$
(D) CO(g) + 2H$_2$(g) $\to$ CH$_3$OH(g) (IV) Ni

Choose the correct answer from the options given below :

  1. A $$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})$$
  2. B $$(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{III})$$
  3. C $$(\mathrm{~A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})$$ Correct answer
  4. D $$(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})$$

Solution

Here, we have to match the reactions with their correct catalyst : <br/><br/> (A) $$\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \stackrel{\mathrm{Fe}_{\mathrm{x}} \mathrm{O}_{\mathrm{y}}+\mathrm{K}_{2} \mathrm{O}+\mathrm{Al}_{2} \mathrm{O}_{3}}{\longrightarrow} 2 \mathrm{NH}_{3}(\mathrm{~g})$$ <br/><br/> (B) $$\mathrm{CO}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{~g}) \stackrel{\mathrm{Ni}}{\longrightarrow} \mathrm{CH}_{4}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{g})$$ <br/><br/> (C) $$\mathrm{CO}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{~g}) \stackrel{\mathrm{Cu}}{\longrightarrow} \mathrm{HCHO}(\mathrm{g})$$ <br/><br/> (D) $$\mathrm{CO}(\mathrm{g})+2 \mathrm{H}_{2}$ (g) $\stackrel{\mathrm{Cu} / \mathrm{ZnO}-\mathrm{Cr}_{2} \mathrm{O}_{3}}{\longrightarrow} \mathrm{CH}_{3}-\mathrm{OH}(\mathrm{g})$<br/><br/>$\therefore$$ Option (C) is correct option.

About this question

Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family

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