Given below are two statements:
Statement I : $\mathrm{S}_8$ solid undergoes disproportionation reaction under alkaline conditions to form $\mathrm{S}^{2-}$ and $\mathrm{S}_2 \mathrm{O}_3{ }^{2-}$.
Statement II : $\mathrm{ClO}_4^{-}$ can undergo disproportionation reaction under acidic condition.
In the light of the above statements, choose the most appropriate answer from the options given below :
Solution
<p>$$\mathrm{S}_1: \mathrm{S}_8+12 \mathrm{OH}^{\ominus} \rightarrow 4 \mathrm{~S}^{2-}+2 \mathrm{~S}_2 \mathrm{O}_3^{2-}+6 \mathrm{H}_2 \mathrm{O}$$</p>
<p>$\mathrm{S}_2: \mathrm{ClO}_4^{\ominus}$ cannot undergo disproportionation reaction as chlorine is present in it's highest oxidation state.</p>
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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