In the leaching of alumina from bauxite, the ore expected to leach out in the process by reacting with NaOH is :
Solution
In bauxite impurities of Fe<sub>2</sub>O<sub>3</sub>, TiO<sub>2</sub> and SiO<sub>2</sub> are present, Fe<sub>2</sub>O<sub>3</sub> and TiO<sub>2</sub> are basic oxides therefore does not reacts with or dissolve in NaOH whereas SiO<sub>2</sub> is acidic oxide it gets dissolve in NaOH, hence leach out<br><br>$Si{O_2} + 2NaOH \to N{a_2}Si{O_3}(aq.) + {H_2}O$
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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