The products obtained from a reaction of hydrogen peroxide and acidified potassium permanganate are :
Solution
$$2 \mathrm{MnO}_{4}^{-}+6 \mathrm{H}^{+}+5 \mathrm{H}_{2} \mathrm{O}_{2} \longrightarrow 2 \mathrm{Mn}^{2+}+8 \mathrm{H}_{2} \mathrm{O}+5 \mathrm{O}_{2}$$
<br/><br/>
This reaction shows reducing action of $\mathrm{H}_{2} \mathrm{O}_{2}$ in acidic medium.
<br/><br/>
The products formed are $\mathrm{Mn}^{2+}, \mathrm{H}_{2} \mathrm{O}$ and $\mathrm{O}_{2}$
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
This question is part of PrepWiser's free JEE Main question bank. 300 more solved questions on p-Block Elements are available — start with the harder ones if your accuracy is >70%.