Borazine, also known as inorganic benzene, can be prepared by the reaction of 3-equivalents of "$X$" with 6-equivalents of "$Y$". "$X$" and "$Y$", respectively are :
Solution
$$3 \mathrm{~B}_{2} \mathrm{H}_{6}+6 \mathrm{NH}_{3} \rightarrow \underset{\text { (Borazine) }}{2 \mathrm{~B}_{3} \mathrm{N}_{3} \mathrm{H}_{6}}$$
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
This question is part of PrepWiser's free JEE Main question bank. 300 more solved questions on p-Block Elements are available — start with the harder ones if your accuracy is >70%.