Easy MCQ +4 / -1 PYQ · JEE Mains 2022

Match List-I with List-II

List - I List - II
(A) Concentration of gold ore (I) Aniline
(B) Leaching of alumina (II) NaOH
(C) Froth stabiliser (III) SO$_2$
(D) Blister copper (IV) NaCN

Choose the correct answer from the options given below :

  1. A (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
  2. B (A) - (IV), (B) - (II), (C) - (I), (D) - (III) Correct answer
  3. C (A) - (III), (B) - (II), (C) - (I), (D) - (IV)
  4. D (A) - (II), (B) - (IV), (C) - (III), (D) - (I)

Solution

Gold is concentrated by cyanidation<br/><br/> Leaching of alumina is done by NaOH<br/><br/> Froth stabiliser is aniline<br/><br/> Blister copper has condensed SO<sub>2</sub> on the surface

About this question

Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family

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