Easy MCQ +4 / -1 PYQ · JEE Mains 2020

Reaction of ammonia with excess Cl2 gives :

  1. A NH<sub>4</sub>Cl and N<sub>2</sub>
  2. B NH<sub>4</sub>Cl and HCl
  3. C NCl<sub>3</sub> and HCl Correct answer
  4. D NCl<sub>3</sub> and NH<sub>4</sub>Cl

Solution

NH<sub>3</sub> + 3Cl<sub>2</sub>(excess) $\to$ NCl<sub>3</sub> + 3HCl

About this question

Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family

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