The nature of oxide $\left(\mathrm{TeO}_2\right)$ and hydride $\left(\mathrm{TeH}_2\right)$ formed by Te , respectively are :
Solution
<p>Tellurium dioxide ($\mathrm{TeO}_2$) acts as an oxidizing agent. This is because it can accept electrons and be reduced from its +4 oxidation state to a lower oxidation state.</p>
<p>Tellurium hydride ($\mathrm{TeH}_2$) is considered acidic. This is due to its relatively low bond dissociation energy, which makes it prone to breaking, releasing protons (H$^+$).</p>
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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