1 mole of $\mathrm{PbS}$ is oxidised by "$\mathrm{X}$" moles of $\mathrm{O}_3$ to get "$\mathrm{Y}$" moles of $\mathrm{O}_2$. $\mathrm{X}+\mathrm{Y}=$ _________.
Answer (integer)
8
Solution
<p>$$\begin{aligned}
& \mathrm{PbS}+4 \mathrm{O}_3 \rightarrow \mathrm{PbSO}_4+4 \mathrm{O}_2 \\
& \mathrm{x}=4, \mathrm{y}=4
\end{aligned}$$</p>
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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