Given below are two statements:
Statement-I : Methane and steam passed over a heated $\mathrm{Ni}$ catalyst produces hydrogen gas.
Statement-II : Sodium nitrite reacts with $\mathrm{NH}_{4} \mathrm{Cl}$ to give $\mathrm{H}_{2} \mathrm{O}, \mathrm{N}_{2}$ and $\mathrm{NaCl}$.
In the light of the above statements, choose the most appropriate answer from the options given below :
Solution
<p>Let's consider each statement:</p>
<p>Statement-I : Methane (CH₄) and steam (H₂O) can indeed react in the presence of a heated nickel catalyst to produce carbon monoxide (CO) and hydrogen gas (H₂). This is known as the steam reforming or steam methane reforming reaction and is industrially significant for hydrogen production. Hence, Statement-I is correct.</p>
<p>Statement-II : Sodium nitrite (NaNO₂) reacts with ammonium chloride (NH₄Cl) to produce nitrogen gas (N₂), water (H₂O), and sodium chloride (NaCl). This is a standard reaction that is often used in inorganic chemistry to produce nitrogen gas. Hence, Statement-II is also correct.</p>
<p>Therefore, the correct answer is Option C: Both the statements I and II are correct.</p>
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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