$\mathrm{H}_{2} \mathrm{O}_{2}$ acts as a reducing agent in :
Solution
$\mathrm{H}_{2} \mathrm{O}_{2}$ act as a reducing agent.
<br/><br/>$2 \stackrel{+1}{\mathrm{Na}}\stackrel{-2}{\mathrm{O}} \stackrel{+1}{\mathrm{Cl}}+\mathrm{H}_{2} \mathrm{O}_{2} \longrightarrow 2 \mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}$
<br/><br/>$\mathrm{Cl}$ from (+1) state changes to $\mathrm{Cl}^{-1}$.
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
This question is part of PrepWiser's free JEE Main question bank. 300 more solved questions on p-Block Elements are available — start with the harder ones if your accuracy is >70%.