Given below are the statements about diborane
(a) Diborane is prepared by the oxidation of NaBH4 with I2
(b) Each boron atom is in sp2 hybridized state
(c) Diborane has one bridged 3 centre-2-electron bond
(d) Diborane is a planar molecule
The option with correct statements is :
Solution
Diborane is prepared by the reaction of NaBH<sub>4</sub> with I<sub>2</sub>.<br><br>2NaBH<sub>4</sub> + I<sub>2</sub> $\to$ B<sub>2</sub>H<sub>6</sub> + 2NaI + H<sub>2</sub><br><br>In diborane, 'B' is sp<sup>3</sup> hybrid, it is Non-planar and two 3c-2e<sup>$-$</sup> bonds are present.
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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