The products obtained during treatment of hard water using Clark's method are :
Solution
In Clark's method lime water is used<br/><br/>
$$
\begin{aligned}
&\mathrm{Ca}\left(\mathrm{HCO}_3\right)_2+2 \mathrm{Ca}(\mathrm{OH})_2 \rightarrow 2 \mathrm{CaCO}_3+2 \mathrm{H}_2 \mathrm{O} \\\\
&\mathrm{Mg}\left(\mathrm{HCO}_3\right)_2+2 \mathrm{Ca}(\mathrm{OH})_2 \rightarrow 2 \mathrm{CaCO}_3+\mathrm{Mg}(\mathrm{OH})_2+2 \mathrm{H}_2 \mathrm{O}
\end{aligned}
$$
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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