A metal (A) on heating in nitrogen gas gives compound B. B on treatment with H2O gives a colourless gas which when passed through CuSO4 solution gives a dark blue-violet coloured solution. A and B respectively, are :
Solution
3Mg(A) + N<sub>2</sub> $\buildrel \Delta \over
\longrightarrow$
Mg<sub>3</sub>N<sub>2</sub>(B) $\buildrel {6{H_2}O} \over
\longrightarrow$ <br>3Mg(OH)<sub>2</sub> + 2NH<sub>3</sub> (colourless gas)
<br><br>CuSO + 4NH<sub>3</sub> $\to$ [Cu(NH<sub>3</sub>)<sub>4</sub>]SO<sub>4</sub> (deep blue solution)
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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