In the following reaction, products (A) and (B) respectively, are :
NaOH + Cl2 $\to$ (A) + side products
(hot and conc.)
Ca(OH)2 + Cl2 $\to$ (B) + side products
(dry)
Solution
NaOH + Cl<sub>2</sub> $\to$ NaClO<sub>3</sub> (A) + 5NaCl + 3H<sub>2</sub>O
<br><br>Ca(OH)<sub>2</sub> + Cl<sub>2</sub> $\to$ Ca(OCl)<sub>2</sub> (B) + CaCl<sub>2</sub> + 2H<sub>2</sub>O
About this question
Subject: Chemistry · Chapter: p-Block Elements · Topic: Group 13: Boron Family
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