Given below are two statements :

Statement I: Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green

Statement II: The green colour observed is due to the formation of copper(I) metaborate

In light of the above statements, choose the most appropriate answer from the options given below :

On treatment with metal salt, boric anhydride forms metaborate of the metal which gives different colours in oxidising and reducing flame. For example, in the case of copper sulphate, following reactions occur. <br/><br/>$$ \mathrm{CuSO}_4+\mathrm{B}_2 \mathrm{O}_3 \mathrel{\mathop{\kern0pt\longrightarrow} \limits_{\left( {Oxidation} \right)}^{Non - lu\min ous\,flame}} \mathrm{Cu}\left(\mathrm{BO}_2\right)_2+\mathrm{SO}_3 $$ <br/><br/>Two reactions may take place in reducing flame (Luminous flame) <br/><br/>(i) The blue-green $\mathrm{Cu}\left(\mathrm{BO}_2\right)_2$ is reduced to colourless cuprous metaborate as : <br/><br/>$$ \begin{aligned} & 2 \mathrm{Cu}\left(\mathrm{BO}_2\right)_2+2 \mathrm{NaBO}_2+\mathrm{C} \stackrel{\text { Luminous }}{\longrightarrow} \\\\ & 2 \mathrm{CuBO}_2+\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7+\mathrm{CO} \end{aligned} $$ <br/><br/>(ii) Cupric metaborate may be reduced to metallic copper and bead appears red opaque. <br/><br/>$$ \begin{aligned} & 2 \mathrm{Cu}\left(\mathrm{BO}_2\right)_2+4 \mathrm{NaBO}_2+2 \mathrm{C} \underset{\text { flame }}{\stackrel{\text { Luminous }}{\longrightarrow}} \\\\ & 2 \mathrm{Cu}+2 \mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7+2 \mathrm{CO} \end{aligned} $$