Arrange the following solutions in the
decreasing order of pOH :
(A) 0.01 M HCl
(B) 0.01 M NaOH
(C) 0.01 M CH3COONa
(D) 0.01 M NaCl
Solution
(A) 10<sup>–2</sup> M HCl $\Rightarrow$ [H<sup>+</sup>] = 10<sup>–2</sup> M $\Rightarrow$ pH = 2 $\Rightarrow$ pOH = 14 - 2 = 12
<br>(B) 10<sup>–2</sup> M NaOH $\Rightarrow$ [OH<sup>–</sup>] = 10<sup>–2</sup> M $\Rightarrow$ pOH = 2
<br>(C) 10<sup>–2</sup> M CH3COO<sup>–</sup>Na<sup>+</sup> $\Rightarrow$ [OH<sup>+</sup>] > 10<sup>–7</sup> $\Rightarrow$ pOH < 7
<br>(D) 10<sup>–2</sup> M NaCl $\Rightarrow$ Neutral pOH = 7
<br><br>Order of pOH value A > D > C > B
About this question
Subject: Chemistry · Chapter: Equilibrium · Topic: Chemical Equilibrium and Kc, Kp
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