If the solubility product of AB2 is 3.20 $\times$ 10–11 M3,
then the solubility of AB2 in pure water is
_____ $\times$ 10–4 mol L–1.
[Assuming that neither kind
of ion reacts with water]
Answer (integer)
2
Solution
<table class="tg">
<thead>
<tr>
<th class="tg-baqh">AB<sub>2</sub></th>
<th class="tg-baqh">⇌</th>
<th class="tg-baqh">A<sup>2+</sup>(aq)</th>
<th class="tg-baqh">+</th>
<th class="tg-baqh">2B<sup>-</sup>(aq)</th>
</tr>
</thead>
<tbody>
<tr>
<td class="tg-baqh"></td>
<td class="tg-baqh"></td>
<td class="tg-baqh">s</td>
<td class="tg-baqh"></td>
<td class="tg-baqh">2s</td>
</tr>
</tbody>
</table>
<br><br>K<sub>sp</sub> = 4s<sup>3</sup> = 3.2 × 10<sup>–11</sup>
<br><br>$\Rightarrow$ s<sup>3</sup> = 8 × 10<sup>–12</sup>
<br><br>$\Rightarrow$ s = 2 × 10<sup>–4</sup>
About this question
Subject: Chemistry · Chapter: Equilibrium · Topic: Chemical Equilibrium and Kc, Kp
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