Medium MCQ +4 / -1 PYQ · JEE Mains 2020

The lanthanoid that does NOT show +4 oxidation state is :

  1. A Tb
  2. B Dy
  3. C Ce
  4. D Eu Correct answer

Solution

Europium (Eu) <br>Atomic No = 63 <br>Electronic configuration = [Xe]4f<sup>7</sup>6s<sup>2</sup> <br>Can show only + 2 and + 3 oxidation state.

About this question

Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals

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