The addition of dilute NaOH to Cr3+ salt solution will give :
Solution
$$C{r^{3 + }} + \mathop {NaOH}\limits_{dil.} \buildrel {} \over
\longrightarrow \mathop {C{r_2}{O_3}.{{({H_2}O)}_n}}\limits_{precipitate} $$
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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