Potassium permanganate on heating at 513 K gives a product which is :
Solution
$$2KMn{O_4}\mathrel{\mathop{\kern0pt\longrightarrow}
\limits_{200^\circ C}^\Delta } \mathop {{K_2}Mn{O_4}}\limits_{Green} + \mathop {Mn{O_2}}\limits_{Black} + {O_2}$$<br><br>In K<sub>2</sub>MnO<sub>4</sub>, manganese oxidation state is +6 and hence it has one unpaired e<sup>$-$</sup>.
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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