Match List - I with List - II, match the gas evolved during each reaction.
| List - I | List - II | ||
|---|---|---|---|
| (A) | $$\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \stackrel{\Delta}{\longrightarrow}$$ | (I) | $\mathrm{H}_{2}$ |
| (B) | $\mathrm{KMnO}_{4}+\mathrm{HCl} \rightarrow$ | (II) | $\mathrm{N}_{2}$ |
| (C) | $\mathrm{Al}+\mathrm{NaOH}+\mathrm{H}_{2} \mathrm{O} \rightarrow$ | (III) | $\mathrm{O}_{2}$ |
| (D) | $\mathrm{NaNO}_{3} \stackrel{\Delta}{\longrightarrow}$ | (IV) | $\mathrm{Cl}_{2}$ |
Choose the correct answer from the options given below :
Solution
$\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \stackrel{\Delta}{\longrightarrow} \mathrm{N}_{2}+4 \mathrm{H}_{2} \mathrm{O}+\mathrm{Cr}_{2} \mathrm{O}_{3}$
<br/><br/>
$\mathrm{KMnO}_{4}+\mathrm{HCl} \longrightarrow \mathrm{KCl}+\mathrm{MnCl}_{2}+\mathrm{Cl}_{2}+\mathrm{H}_{2} \mathrm{O}$
<br/><br/>
$\mathrm{Al}+\mathrm{NaOH}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{Na}\left(\mathrm{Al}(\mathrm{OH})_{4}\right)+\mathrm{H}_{2}$
<br/><br/>
$2 \mathrm{NaNO}_{3}(\mathrm{~s}) \stackrel{\Delta}{\longrightarrow} 2 \mathrm{NaNO}_{2}(\mathrm{~s})+\mathrm{O}_{2}$
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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