The orange colour of $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ and purple colour of $\mathrm{KMnO}_4$ is due to
Solution
<p>$$\left.\begin{array}{l}
\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 \rightarrow \mathrm{Cr}^{+6} \rightarrow \text { No d - d transition } \\
\mathrm{KMnO}_4 \rightarrow \mathrm{Mn}^{7+} \rightarrow \text { No d - d transition }
\end{array}\right\} \text { Charge transfer }$$</p>
About this question
Subject: Chemistry · Chapter: d and f Block Elements · Topic: Properties of Transition Metals
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