Consider the following reactions

$$\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 \xrightarrow[-\mathrm{H}_2 \mathrm{O}]{\mathrm{KOH}}[\mathrm{~A}] \xrightarrow[-\mathrm{H}_2 \mathrm{O}]{\mathrm{H}_2 \mathrm{SO}_4}[\mathrm{~B}]+\mathrm{K}_2 \mathrm{SO}_4$$

The products $[A]$ and $[B]$, respectively are :

1. A $\mathrm{K}_2 \mathrm{Cr}(\mathrm{OH})_6$ and $\mathrm{Cr}_2 \mathrm{O}_3$
2. B $\mathrm{K}_2 \mathrm{CrO}_4$ and $\mathrm{Cr}_2 \mathrm{O}_3$
3. C $\mathrm{K}_2 \mathrm{CrO}_4$ and $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ Correct answer
4. D $\mathrm{K}_2 \mathrm{CrO}_4$ and $\mathrm{CrO}$